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Modern Genetic Analysis Answers to Selected Problems
Chapter 5*

2. | a. b. See question

3.

a. 9 genotypes
b.
c. The number of different genotypes is 3n where n = number of genes. For simple dominantrecessive relations, the number of different phenotypes is 2n, where n = number of genes.
d. A round, yellow plant's genotype can be deduced through either a self-cross or a testcross.
See question

7. | The two genes are on the same chromosome and are 10 map units apart. See question

9. | b See question

11. | Purple (G) is dominant to green (g); cut (P) is dominant to potato (p). See question

12. | a. (1) 9/128; (2) 9/128; (3) 9/64; (4) 55/64. b. (1) 1/32; (2) 1/32; (3) 1/16; (4) 15/16. See question

13. | Assume there is no linkage. The expected values would be that genotypes occur with equal frequency. There are four genotypes in each case (n = 4), so there are 3 degrees of freedom. See question

17. | (1) b a c; (2) b a c; (3) b a c; (4) a c b; (5) a c b. See question

20. | (1) Impossible; (2) meiosis II; (3) meiosis II; (4) meiosis II; (5) mitosis; (6) impossible; (7) impossible; (8) impossible; (9) impossible; (10) meiosis I; (11) impossible; (12) impossible. See question

23. | dots ; Vertical bar × No dots ; horizontal bar (No dots and Vertical bar are dominant) See question

25. | Genes are linked. See question

28.

a. Large (v+) is dominant to vestigial (v) ; Long (s+) is dominant to short (s)
b. Cross 1: v+ / v ; s+ / s+ × v / v ; s / s

Cross 2: v+ / v ; s+ / s × v / v ; s+ / s

Cross 3: v+ / v ; s+ / s × v+ / v ; s / s

Cross 4: v+ / v ; s / s × v / v ; s+ / s

See question

31. | a. The genes for flower color and plant height are linked (on the same chromosome). The position of the gene for leaf width cannot be determined from this data. b. 0.04% See question

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